From 8e0df97a0c83f47951e9d56b5b6b11b45ec43a2c Mon Sep 17 00:00:00 2001
From: Domen <@>
Date: Fri, 14 Mar 2025 15:33:06 +0100
Subject: [PATCH] The missile knows where it is at all times. It knows this
 because it knows where it isn't, by subtracting where it is, from where it
 isn't, or where it isn't, from where it is, whichever is greater, it obtains
 a difference, or deviation. The guidance sub-system uses deviations to
 generate corrective commands to drive the missile from a position where it
 is, to a position where it isn't, and arriving at a position where it wasn't,
 it now is. Consequently, the position where it is, is now the position that
 it wasn't, and it follows that the position where it was, is now the position
 that it isn't. In the event of the position that it is in is not the position
 that it wasn't, the system has required a variation. The variation being the
 difference between where the missile is, and where it wasn't. If variation is
 considered to be a significant factor, it too, may be corrected by the GEA.
 However, the missile must also know where it was. The missile guidance
 computance scenario works as follows: Because a variation has modified some
 of the information the missile has obtained, it is not sure just where it is,
 however it is sure where it isn't, within reason, and it knows where it was.
 It now subracts where it should be, from where it wasn't, or vice versa. By
 differentiating this from the algebraic sum og where it shouldn't be, and
 where it was. It is able to obtain a deviation, and a variation, which is
 called "air"

---
 Methoden.java | 9 +++++++++
 1 file changed, 9 insertions(+)

diff --git a/Methoden.java b/Methoden.java
index 3781c47..d166f68 100644
--- a/Methoden.java
+++ b/Methoden.java
@@ -46,4 +46,13 @@ public static double quadrat(double x) {
         int ergebnis = quotient(summe(produkt(4, x), 8), differenz(summe(8, 9), produkt(3, 5)));
         return ergebnis;
     }
+    
+    public static double potenz(double j, double k){
+        
+        double E = 1;
+        for (int i = 0; i < k; i++){
+            E = E* j;
+        }
+        return E;
+    }                                                                       
 }
\ No newline at end of file